Question

Sum of three consecutive multiple of 8 is 888.find the multiples.

Answer 1

Let's take any three consecutive multiples of 8

16,24,32

These numbers can also be written as 8x,8(x+1),8 (x+2)

where x=2

Like the same way, 'y' is an unkown number then, the consecutive multiples of 8 are

8y , 8 (y+1), 8 (y+2)

Given that....

8y+ 8 (y+1)+ 8 (y+2)=888

Open the brackets..

8y+8y+8+8y+16=888

24x+24=888

24x=888-24

24x=864

x=864/24

x=36

8x=8*36

=288

8 (x+1)=8*37

=296

8 (x+2)=8*38

=304

288+296+304=88

The three multiples are 288,296,304.

Hope it helps.......

Answer 2

$\huge\boxed{\red{\bold{Solution}}}$

✍ let the three consecutive number be x, (x +8) , (x + 16 )..✌

⭐ x + (x +8)+(x+16) = 888

=> x + x+8 + x + 16 = 888

=> 3x + 8 + 16 = 888

=> 3x + 24 = 888

=>3x = 888- 24

=> 3x = 864

=> x = 864/ 3

=> x = 288

So , x = 288

⭐ (x + 8) = 288 + 8 = 296

⭐( x + 16) = 288 + 16 = 304

Hence ,

Three consecutive number be 288, 296 and 304..