Question

sum of three consecutive multiples of 3 is 36 . find the multiples​

Answer 1

Answer:

Let the three consecutive multiples of 3 be x, x+3,x+6.

x+x+3+x+6= 36.

3x+9 = 36.

3x= 27.

x= 9.

x+3= 12.

x+6= 15.

Thus, the three consecutive multiples of 3 is 36 are 9, 12, 15.