Question

sum of three consecutive multiples of 4 is 108 find the ros​

Answer 1

Answer:

8, 9, 10

Step-by-step explanation:

Let the smallest no. multplied be x then other two nos. will be x+1 and x+2

sum of consecutive multiples of four= 4*x + 4*(x +1) + 4×(x+2)

=4x + 4x +4 + 4x + 8 = 108

=12x + 12 = 108

=12(x +1) = 108

=x + 1 = 108/12 ( by transposition of 12 from LHS to RHS)

x+1 = 9

x = 9-1 = 8 ( by transposition of 1 fom LHS to RHS )

So, the smallest no is 8 then the other nos. will be x+1 ie. 9 and x+2 ie. 10

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Answer 2

Answer:

8, 9, 10

Step-by-step explanation:

Let the smallest no. multplied be x then other two nos. will be x+1 and x+2

sum of consecutive multiples of four= 4*x + 4*(x +1) + 4×(x+2)

=4x + 4x +4 + 4x + 8 = 108

=12x + 12 = 108

=12(x +1) = 108

=x + 1 = 108/12 ( by transposition of 12 from LHS to RHS)

x+1 = 9

x = 9-1 = 8 ( by transposition of 1 fom LHS to RHS )

So, the smallest no is 8 then the other nos. will be x+1 ie. 9 and x+2 ie. 10

Step-by-step explanation: