Question

 sum of three consecutive multiples of 4 is 144. Find these multiples.
pls ans asap​

Answer 1

Answer:

The three consecutive multiples of 4 are - 44 , 48 , 52

Step-by-step explanation:

Let the consecutive multiples of 4 be - x , (x+4) , (x+8).

The consecutive multiples of four add up to 144.

So, x + x + 4 + x + 8 = 144

3x + 12 = 144

3x = 144 - 12

3x = 132

x = 132 /3

x = 3.

The consecutive multiples of 4 are -

x = 44

x + 4 = 44 + 4 = 48

x + 8 = 44 + 8 = 52

Therefore, the three consecutive multiples of four that add up to 144 are 44, 48, 52.

Hope it helps ! : )

Answer 2

To find : three multiples of $4$

Given : sum of three consecutive multiples of $4$ is 144.

Solution :

• Let the first multiple of 4 be $4x$ , second consecutive multiple of 4 be $4(x + 1)$ and third multiple of 4 be $4(x + 2 )$.
• Then we write given condition as :  

       $4x + (4x + 4 ) + ( 4x + 8) = 144$

• Now , adding like terms together we get ,

                $12x + 12 = 144$

                        $12x = 144 -12$

                            $x = \frac{132}{12}$

                            $x = 11$

• Substituting  value of $x$ in given multiples  we get,
• First multiple = $x = 11$
• Second multiple = $x + 1 = 11 + 1 = 12$
• Third multiple = $x + 2 = 11 + 2 = 13$

       Hence , multiples are $11, 12 \ and \ 13$.