sum of three consecutive multiples of 4 is 444 find these multiples
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Let , the 1st no. be 4X ,
Second no. be 4X + 4
And third No. be 4X + 8
4X + (4X + 4) + (4X + 8) = 444
12x +12 =444
12X = 144 - 12
12X = 132
X = 132 / 12
X = 36
Therefore the numbers are 144 ,148 And 152
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let the first, second, and convective multiple be x, x+4, x+8 respectively
acq:-
x + x+4 + x+8 = 444
3x + 12 = 444
3x = 444-12
3x = 432
x = 144
therefore 3 consecutive multiples are :
144, 148 and 152
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