Question

Sum of three consecutive multiples of 4 is 60. Find the three numbers

Answer 1

Answer:

Three numbers are 16,20,24.

Step-by-step explanation:

Let the multiples of 4 be x,x+4,x+4+4

x+x+4+x+4+4= 60

3x+12. = 60

3x. = 60-12

3x. = 48

x. = 48/3

$\boxed{x= 16}$

Therefore,

First multiple = x+4

=16+4

=20

Second multiple = x+4+4

=16+8

=24

☆Verification☆

16+20+24

36+24

60

Answer 2

Answer:

Let the three consecutive multiples of 4 be 4x, 4(x+1) and 4(x+2)

Given : sum of three consecutive multiples of 4 = 60

4x + 4 (x+1)+ 4(x+2) = 60

4x + 4x + 4 + 4x + 8 = 60

12x + 12 = 60

12x = 60 - 12

12 x = 48

$x = \frac{48}{12} = 4 \\ x = 4 \\ 4x = \: 4 \times 4 = 16 \\ 4(x + 1) = 4(4 + 1) = 4(5) = 20 \\ 4(x + 2) = 4(4 + 2) = 4(6) = 24$

✅ hence the required numbers are 16, 20 and 24.

HOPE IT HELPS YOU ⛄