Question

SUM OF THREE CONSECUTIVE MULTIPLES OF 5 IS 390. FIND THE SMALLEST MULTIPLE AMONG THREE.

Answer 1

Step-by-step explanation:

let 1 multiple be 5x

second be 10 X

third be 15x

5x +10x +15x = 390

30x = 390

x = 390/30

x = 13

first number be 13×5 =60

second number be 13×10 = 130

third number = 13×15 =195

hence 30 is smallest

Answer 2

Given : -

Consecutive Multiples of 5 is = 390.

To Find : -

Smallest Multiple among three.

Solution : -

Sum of three consecutive multiples is = 5x , 10x , 15x

Now : -

$\sf{5x+10x+15x=390}$

30x = 390

x = 390/30

x = 13

So , the value of x is 13 ..

Hence : -

1st Consecutive Multiple is = 5(x)

= 5(13)

= 65

2nd Consecutive Number is = 10(x)

= 10(13)

= 130

3rd Consecutive Number is = 15(x)

= 15(13)

= 195

Therefore , the three consecutive Multiples are 65 , 130 , 195 and the smallest among these three is 65 ..