sum of three consecutive multiples of 5 is 390, find the smallest multiple
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Answer:
125
Step-by-step explanation:
Let the three consecutive multiple of 5= x,x+5,x+10
Given that sum of three consecutive multiple of 5 is 390.
therefore,x+(x+5)+(x+10)=390
or,x+x+5+x+10=390
or,3x+15=390
or,3(x+5)=390
or,x+5=390/3
or,x=130-15
or, x=125
thus smallest multiple of 5=x=125
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