Question

Sum of three consecutive multiples of 6 is 648. One of these multiple is?
240
300
216
360​

Answer 1

Answer:

SOLUTION

Let the first multiple of 6 be x

Second multiple = x+6

Third multiple = x+6+6 = x+12

According to Question:

x+x+6+x+12 = 666

=>3x + 18 = 666

=>3x = 666-18 = 648

=>x = 648/3

=>x = 216

x+6 = 222

x+12 = 228

So, the multiples are 216, 222 and 228.