Question

Sum of three consecutive multiples of 6 is 666. One of these multiple is

Answer 1

Let smallest multiple be x

so others two are x + 6 , x + 12

by the condition given in your question we get equation

x + x + 6 + x + 12 = 666

3x + 18 = 666

3x = 648

x = 648/3

x = 216

x + 6 = 222

x + 12 = 228

so three multiples are 216 , 222 , 228

Answer 2

Let,

The first multiple of 6 be x

Second multiple = x+6

Third multiple = x+6+6 = x+12

A/q

x+x+6+x+12 = 666
=>3x + 18 = 666
=>3x = 666-18 = 648
=>x = 648/3
=>x = 216

Hence,
x=216
x+6 = 222
x+12 = 228

So, the multiples are 216, 222 and 228.


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