Question

sum of three consecutive multiples of 7 is 357 find the numbers

Answer 1

let the no be=x
x+7,x+14
x+x+7+x+14=357
3x+21=357
by transposing 21 to RHS
3x=357-21
3x=336
by transposing 3 to RHS
x=336/3
x=112
hence the first no =112
the second no is =x+7=112+7=119
the third no is =x+14=112+14=126
I hope this is useful for you ....

Answer 2

Answer:

The smallest multiple of $7$ is $112$.

Step-by-step explanation:

Given:

The sum of three consecutive multiples of 7 is 357.

To find:

The numbers.

Step 1

Let the $3$ consecutive multiples of $7$ be $7,(7 x+7),(7 x+14)$ where $x$ is a natural number.

As per the question,

$7+(7 x+7)+(7 x+14)=357$

$\Rightarrow 21 x+21=357$

Taking $21$ as the common term

$\Rightarrow 21(x+1)=357$

Step 2

Divide both sides by $21$,

$\Rightarrow \frac{21(x+1)}{21}=\frac{357}{21}$

$\Rightarrow x+1=17$

$\Rightarrow x=17-1 \text$  (transpose $1$ to RHS)

therefore $x=16$

Hence, the smallest multiple of $7$ is

$7 \times 16$ $=112$.

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