Sum of three consecutive multiples of 8 is888 find the multiples
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sum=888
a=?
d=8
no. of terms=3
Sn=n/2(2a+(n-1)d)
888=3/2(2a+(3-1)d)
888=3/2(2a+2×8)
888=3a+24
864=3a
a=864/3
so,a=288
therefore the multiples are
288,296,304
a=?
d=8
no. of terms=3
Sn=n/2(2a+(n-1)d)
888=3/2(2a+(3-1)d)
888=3/2(2a+2×8)
888=3a+24
864=3a
a=864/3
so,a=288
therefore the multiples are
288,296,304
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