Question

Sum of three consecutive natural number is 45. How much is the difference between the square of the extreme terms more than the square of the difference between extreme terms

Answer 1

call n the first integer
n+(n+1)+(n+2)=45
3n+3=45
3n=42
n=14
15
16
please mark as brainliest

Answer 2

Answer:

call n the first integer

n+(n+1)+(n+2)=45

3n+3=45

3n=42

n=14

15

16

Please mark ME as brainliest

HOPE IT HELPS