Question

Sum of three consecutive number is 11 . Find numbers .
Explain step by step​

Answer 1

$\sf\red{\underline{\underline{Answer:}}}$

$\sf{Numbers \ are \ \frac{8}{3}, \ \frac{11}{3} \ and \ \frac{14}{3}}$

$\sf\orange{Given:}$

$\sf{\implies{Sum \ of \ three \ consecutive \ numbers \ is \ 11}}$

$\sf\pink{To \ find:}$

$\sf{The \ numbers.}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{Consecutive \ numbers \ have \ difference \ of \ 1}$

$\sf{\therefore{Let \ the \ three \ numbers \ be}}$

$\sf{(x-1), \ x \ and \ (x+1)}$

$\sf{According \ to \ the \ given \ condition}$

$\sf{(x-1)+x+(x+1)=11}$

$\sf{\therefore{3x=11}}$

$\boxed{\sf{\therefore{x=\frac{11}{3}}}}$

$\sf{Number \ (x-1)=\frac{11}{3}-1=\frac{8}{3}}$

$\sf{Number \ x=\frac{11}{3}}$

$\sf{Number \ (x+1)=\frac{11}{3}+1=\frac{14}{3}}$

$\sf\purple{\tt{\therefore{Numbers \ are \ \frac{8}{3}, \ \frac{11}{3} \ and \ \frac{14}{3}}}}$

Answer 2

letone of the consecutive number be n

11=n+1+n+2+n

11 =3n+3

11-3=3n

8=3n

so n equals to 8/3

other two are

11/3 and 14/3

I am not writing the numbers in decimal form because you asked for numbers so I have written rational numbers.

hope it helps

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