sum of three consecutive number is 330 then find 3/4 of greatest number
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THATS A WRONG ANSWER,THERE IS A CALCULATION MISTAKE!!!!!
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Let the three consecutive number be
X, x+1,x+2
So,
X + x + 1 + x + 2 = 330
3x + 3 = 330
3x = 330 - 3
3x = 327
X = 327/3
X = 109
So,the numbers are
109
110
111
Then, 3/4 of the greatest number =
3/4 of 111
=83 1/4
It can also be written as 83.25
X, x+1,x+2
So,
X + x + 1 + x + 2 = 330
3x + 3 = 330
3x = 330 - 3
3x = 327
X = 327/3
X = 109
So,the numbers are
109
110
111
Then, 3/4 of the greatest number =
3/4 of 111
=83 1/4
It can also be written as 83.25
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