Question

sum of three consecutive number is 366 . out of this one number is the square ​

Answer 1

Answer:

The correct answer is:

Step-by-step explanation:

121,122,123

PREMISES

x+(x+1)+(x+2)=366

ASSUMPTIONS

Let three consecutive numbers= x, x+1,x+2

CALCULATIONS

(1) x+(x+1)+(x+2)=366

(2) 3x+(1+2)=366

(3) 3x+3=366

(4) 3x/3+(3–3)=(366–3)/3

(5) x+0=363/3

(6) x=

121

CONCLUSIONS

If x=121, then x+1 and x+2 =122 and 123 respectively

PROOF

(1) x+(x+1)+(x+2)=366 yields

(2) 121+122+123=366 and

(3) 366=366 proves that 121,122, and 123 are three consecutive numbers whose sum=366