Question

Sum of three consecutive numbers is 159. Find the numbers. with explaination too

Answer 1

Question

Sum of three consecutive numbers is 159. Find the numbers. Provide explanation for your answer too.

$\rule{300}{1}$

Answer

Algebra must be used in this question.

Let the 1st number be ⇒ y

Let the 2nd consecutive number be ⇒ y+1

Let the 3rd consecutive number be ⇒ y+2

So our equation now will be written as ⇒ (y) + (y + 1) + (y + 2) = 159

Let's solve your equation step-by-step.

(y) + (y + 1) + (y + 2) = 159

Step 1: Simplify both sides of the equation.

y + y + 1 + y + 2 = 159

(Combine Like Terms)

(y + y + y) + (1 + 2) = 159

3y + 3 = 159

Step 2: Subtract 3 from both sides.

3y + 3 - 3 = 159 - 3

3y = 156

Step 3: Divide both sides by 3.

3y ÷ 3 = 156 ÷ 3

y = 52

So now let's find the three consecutive numbers with the value of 'y'.

The 1st number would be ⇒ y = 52

The 2nd consecutive number would be ⇒ y+1 = 52 + 1 = 53

The 3rd consecutive number would be be ⇒ y+2 = 52 + 2 = 54

Let's verify if these are the three consecutive numbers that sums upto 159.

52 + 53 + 54 = 156

∴ Let the 1st be ⇒ 52

∴ Let the 2nd consecutive number be ⇒ 53

∴ Let the 3rd consecutive number be ⇒ 54

$\rule{300}{1}$

Answer 2

Answer:

✡ QUESTION ✡

➡ Sum of three consecutive numbers is 159. Find the numbers.

✡ To Find ✡

➡ Number

✡ Solution ✡

➡ Let the 1st number be = y

➡Let the 2nd consecutive number be = y+1

➡Let the 3rd consecutive number be = y+2

▶ So we get an new equation

⭐ (y) + (y + 1) + (y + 2) = 159 ⭐

✏ According to the question:-

▶ $\huge \bold{ \underline{ \mathbb{ \blue{</em><em>STEP</em><em> </em><em>1</em><em> </em><em>}}}}$

Simplify both sides of the equation.

=> y + y + 1 + y + 2 = 159 (Combine Like Terms)

=>(y + y + y) + (1 + 2) = 159

=>3y + 3 = 159

▶ $\huge \bold{ \underline{ \mathbb{ \blue{STEP 2}}}}$

Subtract 3 from both sides.

=> 3y + 3 - 3 = 159 - 3

=> 3y = 156

▶ $\huge \bold{ \underline{ \mathbb{ \blue{</em><em>STEP</em><em> </em><em>3</em><em>}}}}$

Divide both sides by 3.

=> 3y ÷ 3 = 156 ÷ 3

=> y = 52

So we have to find the three consecutive numbers with the value of 'y'.

➡The 1st number would be ⇒ y = 52

➡The 2nd consecutive number would be ⇒ y+1 = 52 + 1 = 53

➡The 3rd consecutive number would be be ⇒ y+2 = 52 + 2 = 54

✏We have to verify that if these are the three consecutive numbers that sums upto 159.

=> 52 + 53 + 54 = 156

⚫Let the 1st be = 52

⚫Let the 2nd consecutive number be = 53

⚫ Let the 3rd consecutive number be ⇒ 54

Step-by-step explanation:

HOPE IT HELP YOU