sum of three consecutive numbers is 2262. What is 41% of the highest number
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Let the numbers be x, x + 1, x + 2
So,
X + x + 1 + x + 2 = 2262
=> 3x + 3 = 2262
=> 3x = 2262 - 3
=> 3x = 2259
=> x = 2259/3
=> x = 753
So, the numbers are
753, 754, 755
The highest number among them are - 755.
So, 41% of 755
= 41/100 of 755
=309.55
Hope it helps...!!!
So,
X + x + 1 + x + 2 = 2262
=> 3x + 3 = 2262
=> 3x = 2262 - 3
=> 3x = 2259
=> x = 2259/3
=> x = 753
So, the numbers are
753, 754, 755
The highest number among them are - 755.
So, 41% of 755
= 41/100 of 755
=309.55
Hope it helps...!!!
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