Math, asked by rmontu223, 7 months ago

Sum of three consecutive
numbers is 33.The middle one is
10
12
15​

Answers

Answered by Anonymous
1

Let the three consecutive numbers be x,(x+1),(x+2)

ATP

x+(x+1)+(x+2) = 33

=) x+x+x+1+2 = 33

=) 3x+3 = 33

=) 3x = 33-3

=) x = 30/3 = 10

Ans:- 10,11,12

Answered by mdjamaluddin9931
0

Answer:

= 11

11 is the answer but, this is not in your option.

Step-by-step explanation:

Let the first consecutive number be x

the second consecutive number be 2x

the third consecutive number be 3x

A/q

= x+2x+3x=33

= 6x=33

= x=33/6

= x=11/2

Then, the number is

1. x=11/2

2. 2x=2×11/2=11

3. 3x=3×11/2=33/2

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