Question

sum of three consecutive numbers is 48 find the numbers​

Answer 1

$\Huge\mathfrak\green{AnsweR:}$

${}$

$\bf{{\underline{Given}}:}$

• The sum of three consecutive numbers are 48.

$\bf{{\underline{To~find}}:}$

• The three consecutive numbers

$\bf{{\underline{Solution}}:}$

• Let the three consecutive numbers be $\sf{x,~(x+1)}$ and $\sf{(x+2)}$

$\rm{:\longmapsto x+(x+1)+(x+2)=48}$

$\rm{:\longmapsto 3x+3=48}$

$\rm{:\longmapsto 3x=48-3}$

$\rm{:\longmapsto 3x=45}$

$\rm{:\longmapsto x={\dfrac{45}{3}}}$

$\rm{:\longmapsto x=\green{\underline{\boxed{\bf 15}}}}$

$\bf\therefore{{\underline{Required~answer}}:}$

• The three consecutive numbers are :
• $\sf{x=\green{\underline{\boxed{\bf 15}}}}$
• $\sf{x+1=15+1=x=\green{\underline{\boxed{\bf 16}}}}$
• $\sf{x+2=15+2=x=\green{\underline{\boxed{\bf 17}}}}$

$\bf{{\underline{Verification}}:}$

• $\sf{15+16+17=\green{\underline{\boxed{\bf 48}}}}$

Answer 2

Answer:

:

The sum of three consecutive numbers are 48.

\bf{{\underline{To~find}}:}To find:

The three consecutive numbers

\bf{{\underline{Solution}}:}Solution:

Let the three consecutive numbers be \sf{x,~(x+1)}x, (x+1) and \sf{(x+2)}(x+2)

\rm{:\longmapsto x+(x+1)+(x+2)=48}:⟼x+(x+1)+(x+2)=48

\rm{:\longmapsto 3x+3=48}:⟼3x+3=48

\rm{:\longmapsto 3x=48-3}:⟼3x=48−3

\rm{:\longmapsto 3x=45}:⟼3x=45

\rm{:\longmapsto x={\dfrac{45}{3}}}:⟼x=345

\rm{:\longmapsto x=\green{\underline{\boxed{\bf 15}}}}:⟼x=15

\bf\therefore{{\underline{Required~answer}}:}∴Required answer:

The three consecutive numbers are :

\sf{x=\green{\underline{\boxed{\bf 15}}}}x=15

\sf{x+1=15+1=x=\green{\underline{\boxed{\bf 16}}}}x+1=15+1=x=16

\sf{x+2=15+2=x=\green{\underline{\boxed{\bf 17}}}}x+2=15+2=x=17

\bf{{\underline{Verification}}:}Verification:

\sf{15+16+17=\green{\underline{\boxed{\bf 48}}}}15+16+17=48