sum of three consecutive numbers is 63 then find the product of extremes
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HELLO DEAR,
LET x-1, x, x+1 BE THE NUMBERS.
THEN ,
(x-1) + x + (x+1) = 63
3x = 63
x = 21
=> x-1 = 20 and x+1 = 22. THEIR PRODUCT IS 440.
I HOPE ITS HELP YOU DEAR,
THANKS
LET x-1, x, x+1 BE THE NUMBERS.
THEN ,
(x-1) + x + (x+1) = 63
3x = 63
x = 21
=> x-1 = 20 and x+1 = 22. THEIR PRODUCT IS 440.
I HOPE ITS HELP YOU DEAR,
THANKS
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