Question

sum of three consecutive of 8 in 888 find the multiples
​

Answer 1

Let the multiples are x, (x+1) and (x+2).

The sum of three consecutive multiples of 8 = 888

According to condition,

8x+8(x+1)+8(x+2) = 888

or, 8x+8x+8+8x+16 = 888

or, 24x+24 = 888

or, 24x = 888-24

or, 24x = 864

or, x = 864/24

or, x = 36

So, x = 36,

(x+1) = (36+1) = 37,

and (x+2) = (36+2) = 38.

Hence, the multiples are 36, 37 and 38 respectively.