Question

Sum of three consecutive of an A.P is 30 and their product is 360 find the terms

Answer 1

Answer:

2,10,18

Step-by-step explanation:

Let the no.s be (a-d),a,(a+d)

(a-d)+a+(a+d)=30

a+a+a=30

3a=30

a=10

(a-d)*a*(a+d)=360

(10-d)*10*(10+d)=360

(10-d)*(10+d)=36

(10)^2 - d^2=36

d^2=100-36

d^2=64

d=√64

d=8

a=10

d=8

a-d=2

a=10

a-d=18