Question

sum of three consecutive terms in AP is 6 and their product is 6 find the three number​

Answer 1

let three terms be a-d, a,a+d so

a+d+a+a-d=6

3a=6

a=2

so

a+d×a-d×a=6

2+d ×2-d ×2= 6

4-d^2=3

d=+-√3/2

so a a+d a-d is determined