Sum of three consecutive terms of an Arithmetic Progression is 42 and their product is 2520.
Find the terms of the Arithmetic Progression.
Answers
Answered by
4
Answer:
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Step-by-step explanation:
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Answered by
3
Answer:
10 , 14 , 18
Step-by-step explanation:
let the 3 consecutive no, be a - d, a , a + d
sum =42
a - d + a +a + d = 42
3a = 42
a = 14
product = 2520
(a -d ) (a ) (a + d) =2520
( a² -d²) (a) =2520
(14² - d²) x14 = 2520
196 -d² = 2520 /14
-d² = 180 -196
-d² = 16
∴ d = 4
the 3 no, are (14 - 4) , 14 ,( 14 +4)
= 10 , 14, 18
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