Question

sum of three consecutive terms of an arithmetic sequence is 33 and the product of this term is 1287. find the terms?

Answer 1

Answer:

Step-by-step explanation:

a-d+a+a+d=33

3a=33

a=11

(a-d)(a)(a+d)=1287

(a²-d²)(11)=1287

(11²-d²)=117

d²=121-117

d²=4

d=2

So the terms after substitution are:

9,11,13