sum of three consecutive vmultiples of 4 is 108 find theros
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Answer:
Step-by-step explanation:
The numbers are 33, 36 and 39.
Explanantion:
Let us suppose, the numbers are x, x +3 and x+6
Sum of them is:
x + (x +3) + (x+6) = 108
=> 3x + 9 = 108
=> 3x = 99
=> x = 33, which is divisible by 3
So the number are 33 (x), 36 (x+3) and 39 (x+6).
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