Question

Sum of three digit number is 17. Sum of squared of digits of the given num is 109. If we subtract 495 from that num we will get a number written in square order. Find the num ?

Answer 1

Step-by-step explanation:

sum of the three digit is 17..hence a+b+c=17----(1)

sum of squared of digits is 109 ..hence a^2+b^2+c^2=109----(2)

Also, 100a+10b+c-495=100c+10b+a

99(a-c)=495

a-c=5

The possible combinations are (6,1)(7,2)(8,3),(9,4)

out of these combinations 8,3 oly satisfies both (1) nd (2)

8+b+3=17

b=6

hence 8+6+3=17

8^2+6^2+3^2=64+36+9=109

so,863 is ans..