Question

Sum of three even consecutive numbers is 192 find the numbers

Answer 1

The numbers are 62 , 64 , 66

Given :

Sum of three even consecutive numbers is 192

To find :

The numbers

Solution :

Step 1 of 2 :

Form the equation

Let the numbers are n , n + 2 , n + 4

Here it is given that Sum of three even consecutive numbers is 192

By the given condition

n + ( n + 2 ) + ( n + 4 ) = 192

Step 2 of 2 :

Find the numbers

n + ( n + 2 ) + ( n + 4 ) = 192

⇒ 3n + 6 = 192

⇒ 3n = 186

⇒ n = 186/3

⇒ n = 62

First number = n = 62

Second number = n + 2 = 62 + 2 = 64

Third number = n + 4 = 62 + 4 = 66

The numbers are 62 , 64 , 66

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Answer 2

Given,

Sum of three even consecutive numbers = 192

To find,

The three even consecutive numbers.

Solution,

We can simply solve this mathematical problem using the following process:

Let us assume that the three even consecutive numbers be (2n-2), 2n, and (2n+2), respectively.

{Since any even number must be of the format 2m, where m is any integer}

Now, according to the question)

Sum of the three even consecutive numbers = 192

=> (2n-2) + 2n + (2n+2) = 192

=> 2n - 2 + 2n + 2n + 2 = 192

=> 6n = 192

=> n = 32

So, the first number is (2n-2) = 2(32) - 2 = 62

The second number is = 2n = 2(32) = 64

The third number = (2n+2) = 2(32) + 2 = 66

Hence, the three even consecutive numbers are 62, 64, and 66, respectively.