Question

sum of three expression is 8+13a+7a²,among them two expressions are 2a²+3a+2 and 3a²+4a+2.find the third expression​

Answer 1

Answer:

we know that

perimeter of triangle=sum of all sides

:let's third side be x

=> (2a²+3a+2)+(3a²-4a-1)+x

=> 8+13a+7a²

=> (5a²-a+1)+x=8+13a+7a²

=> x=8+13a+7a²-(5a²-a+1)

=> x=8+13a+7a²-5a²+a-1

=> x=2a²+14a+7

Hence, third side be 2a²+14a+7

Hope it help you