sum of three number in AP is 24 and product 440 find number
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Answered by
1
Answer:
the three numbers are 5, 8, and 11.
Step-by-step explanation:
If the sum of three numbers in A.P., is 24 and their product is 440, find the numbers. Let the three numbers in A.P. be a – d, a, and a + d. Therefore, when d = 3, the numbers are 5, 8, and 11 and when d = –3, the numbers are 11, 8, and 5. Thus,
the three numbers are 5, 8, and 11.
hope it helps u.....,
Answered by
1
Answer:
Let the 3 consecutive numbers be , ( a-d) , a , (a+d)
a-d+a+a+d = 24
3a=24
a=8
(a-d).a.(a+d)=440
(a^2 - d^2 ) a = 440
(8^2 - d^2)8=440
d^2 = 9
d=+3 or d=-3
Terms : (8-3),8,(8+3) ; 5,8,11,.
(8+3),8,(8-3) ; 11,8,5,..
Hope this answer is help ful for you
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