sum of three numbers in AP is 21 product of first and third number of the sequence is 45 what are the three numbers
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Answer:
5,7,9
Step-by-step explanation:
let let the numbers be a+d,a,a-d
a+d+a+a-d=21
3a=21
a=7
and (a+d)(a-d)=45
a²-d²=45
d²=4
d=±2
hence the numbers are 5,7,9 when d= 2 and 9,7,5 when d=-2. so in both the given cases the number are same.
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