Question

Sum of three numbers in Arithmetic progress is -3 and their product is 8 find the numbers

Answer 1

Answer:

let the no.s be (a-d),(a),(a+d)

sum= a-d+a+a+d=-3

3a=-3

a=-1

product=(a-d)(a)(a+d)=8

(-1-d)(-1)(-1+d)=8

(1+d)(-1+d)=8

-1-d+d+d²=8

d²=9

d=±3

therefore, the no.s are either

-4,-1,2 or 2,-1,-4

hope it helps u....^_^

Answer 2

Answer:

There can be several answers of this question (-4,-1,2) and (2,-1,-4)