Question

Sum of three numbers is 116. The ratio of second number and third number is 9:16 and the ratio of first and third is 1:4 . Then the second number is.

Answer 1

Answer:

Step-by-step explanation:

Let 3 numbers are x , y , z respectively

From 1st condition

x + y + z = 116 ............ (1)

From 2nd condition

y/z = 9/16

16 y = 9x. ................. (2)

From 3rd condition

x/z = 1/4

4x = z ..................... (3)

Put 4x = z in equation( 1 )

X + y + 4 x = 116

5x + y =116 ...............(4)

From 2nd x = 16y/9 put this in (4)

16y /8 + y = 116

(16y^2 + 8 ) / y = 116

16y^2 + 8 = 116 y

16y^2 - 116y + 8 = 0

Divided by 4

4y^2 - 29 y + 2 = 0

After solving this you get value of y and you get 2nd number