Question

Sum of three numbers is 132. First no. is twice the second and third no. is one third of the first. Find the second number.

Answer 1

Answer:

Let the second no. be x

Then,the first no.=2x

and third no.= 2x/3

A/Q

x+2x+2x/3=132

=> 3x+6x+2x/3=132

=> 11x=132×3

=> x=132×3/11

=> x= 36

THUS, THE SECOND NUMBER IS 36.

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Answer 2

Answer:

36

Step-by-step explanation:

Let second number be 3N, then, first one is 6N and the third one is 2N.

From question 3N + 6N + 2N = 132

⇒ 11N = 132

⇒ N = 12

∴ Second number = 3N = 3 x 12 = 36

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