Math, asked by anoushkav, 1 year ago

sum of three numbers is 60 such that twice the first, 3 times the second and 4 times the third together make 180. first number is 3 more than the second one. find the numbers

Answers

Answered by gaurav2013c
27
Let the numbers be b+ 3, b and a

According to first condition

a + b + b + 3 = 60

=> a + 2b = 57

=> 4a + 8b = 228 -----(1)

According to second condition,

2 ( b + 3) + 3b + 4a = 180

=> 2b + 6 + 3b + 4a = 180

=> 4a + 5b = 174 -----(2)

On subtracting equation 2 from 1, we get

3b = 54

=> b = 18

Now,

On putting the value of b in equation 1, we get

=> a + 36 = 57

=> a = 21

First number = b + 3 = 18 + 3 = 21

Second number = 18

Third number = 21
Answered by PriyaGour1316
5

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