Question

sum of three numbers whose ratio are 3*1/3:4*1/5:6*1/8 is 4917 find the number​

Answer 1

Answer:

Simplifying ratio,

So that it will become:

10

3

:

21

5

:

49

8

let common multiple be x.

So, numbers will be:

10

3

x

,

21

5

x

a

n

d

49

8

x

S

o

,

10

3

x

+

21

5

x

+

49

8

x

=

4917

400

x

+

504

x

+

735

x

120

=

4917

1639

x

=

4917

×

120

x

=

360

Substitute value of x,

we get numbers be:

10

3

(

360

)

,

21

5

(

360

)

a

n

d

49

8

(

360

)

=

1200

,

1512

a

n

d

2205

Answer 2

Answer:

let first no be =3 1/3

=10x /3

Step-by-step explanation:

let second no be=4 1/5x

=21x /5

let 3rd no. be= 6 1/8x

=49X/8

AnNa

10x/3 : 21x/5 : 49x/8

take LCM of denominators3,5,8=120

400x: 504x:735x =4917

120

1639x =4917

120

x=4917 ×120

1639

x=360

now ; put value of x in 1st, 2nd ,3rd no

10×360/3=1200

21×360/5=1512

49×360/8=2205