Question

Sum of three prime number is 80. The difference of two of them is 4, find the number

Answer 1

The three prime numbers whose sum is 80

and difference of two of them is 4 are 41,37,2.

As you can see

41+ 37+2=78+2=80

41-37=4.

You must be thinking how i got this result.You have to choose two primes such that their difference is four.Such primes are (3,7),(7,11),(13,17),(19,23),(37,41),(43,47).

So, choose one of them and then find the other prime.

So, your result which satisfy the above condition are  41,37,2.