Question

sum of three terms of an ap is 18 and it's product is 192. find these terms​

Answer 1

Answer:

According to AP:

Let the three numbers be: (x-y) , x , (x+y)

From question we came to know,

x-y+x+x+y = 18 ………………(i)

and

(x-y) x (x+y) = 192 ………… (ii)

Taking equation (i),

x-y+x+x+y = 18

3x = 18

x= 18/3

x = 6

Taking equation (ii),

(x-y) x (x+y) = 192

x (x² - y²) = 192

putting the value of x:

6 ( 6² - y² ) =192

6 ( 36 - y²) =192

216 - 6y² = 192

216 - 192 = 6y²

24 = 6y²

y² = 24/6

y² = 4

y = √4

y = 2

Finding the numbers:

(x-y): (6 - 2) = 4

x: 6

(x+y): (6 + 2) = 8

Required number: 4, 6, 8

Step-by-step explanation:

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