Sum of three terms of an ap is 27 and their product is 405
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Answered by
7
Three term are:- (a-d), a, (a+d)
Given,
Sum=27. (a-d)+a+a-d=27
3a=27
a=9
Product=405
(a-d)(a)(a+d)=405
a(a^2-d^2)=405
Pitting value of a. we get
81-d^2=45
d^2=36
d=6
Therefore,a=9 and d=6
Answered by
1
Answer:
Step-by-step explanation:
Three term are:- (a-d), a, (a+d)
Given,
Sum=27. (a-d)+a+a-d=27
3a=27
a=9
Product=405
(a-d)(a)(a+d)=405
a(a^2-d^2)=405
Pitting value of a. we get
81-d^2=45
d^2=36
d=6
Therefore,a=9 and d=6
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