Question

Sum of three terms of an ap is 27 and their product is 405

Answer 1

Three term are:- (a-d), a, (a+d)

Given,

Sum=27. (a-d)+a+a-d=27

3a=27

a=9

Product=405

(a-d)(a)(a+d)=405

a(a^2-d^2)=405

Pitting value of a. we get

81-d^2=45

d^2=36

d=6

Therefore,a=9 and d=6

Answer 2

Answer:

Step-by-step explanation:

Three term are:- (a-d), a, (a+d)

Given,

Sum=27. (a-d)+a+a-d=27

3a=27

a=9

Product=405

(a-d)(a)(a+d)=405

a(a^2-d^2)=405

Pitting value of a. we get

81-d^2=45

d^2=36

d=6

Therefore,a=9 and d=6