sum of three terms of an arithmetic progression is 30 and their product is 750. find the terms
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we let number are a+d,a,a-d
a+d+a+a-d=30
3a=30
a=10
(10-d)(10)(10+d)=750
(10²-d²)×10=750
100-d²=75
- d²=-25
d=✓25
d=5
term are (10-5)(10)(10+5)
=5,10,15...........
a+d+a+a-d=30
3a=30
a=10
(10-d)(10)(10+d)=750
(10²-d²)×10=750
100-d²=75
- d²=-25
d=✓25
d=5
term are (10-5)(10)(10+5)
=5,10,15...........
bishtashish096:
thank you so much
welcome
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