Question

Sum of three times a number and eight times another number is 19 . Four times the second mumber subtracted from seventeen times the first number give 9. Find the numbers​

Answer 1

Answer:

Step-by-step explanation:

x=67/63

y=83/42

Answer 2

Answer:

The first no. is 1 and the other is 2

Step-by-step explanation:

Let the first no. be $x$ and the other no. be $y$

ATQ,

$3x + 8y = 19$ ... (i)

and

$17x - 4y = 9$ ...(ii) × 2

Adding (i) and (ii),

   $3x + 8y = 19$

   $34x - 8y = 18$

____________      

   $37x$         $= 37$

→ $x = 1$

From (i),

→    $3x + 8y = 19$

→   $3(1) + 8y = 19$

→   $3 + 8y = 19$

→   $8y = 19-3$

→   $8y = 16$

→   $y = 2$

Hope it helps!

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