Sum of two angles of a triangle is 80° and their difference is 20°.find all the angles.
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Answered by
391
Let a,b,c be the angles of triangle
Given a+b=80&a-b=20
Add both
(a+b)+(a-b)=80+20
2a=100
a=50
b=80-50=30
c=180-(50+30)=180-80
=100
Angles of the triangle are 100,50&30
Given a+b=80&a-b=20
Add both
(a+b)+(a-b)=80+20
2a=100
a=50
b=80-50=30
c=180-(50+30)=180-80
=100
Angles of the triangle are 100,50&30
Answered by
118
Hi dear here is your answer.
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