Sum of two angles of a triangle is 90° and their difference is 50°. Find the angles of the b
triangle
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in ABC,
angleA + angleB = 90° ------------(1)
angleA - angleB = 50°-------------(2)
angleA + angleB + angleC = 180° (angle sum property)--------(3)
substituting value if eq (1) in eq(3)
90° + angleC = 180°
angleC= 180°-90°= 90°
adding eq(1) & (2)
angleA + angleB +angleA - angleB = 90° +50°
2angleA = 140°
angleA = 70°
angleA + angleB = 90°
70° + angleB = 90°
angleB = 20°
Therefore, angleA= 70°
angleB = 20°
angleC = 90°
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