Question

Sum of two
conjugetive odd numbers
Square is 202. Find two numbers.​

Answer 1

Answer:

${(n + 1)}^{2} + {(n + 3)}^{2} = 202 \\ 2 {n}^{2} + 10 + 8n = 202 \\ {n}^{2} + 5 + 4n = 101 \\ {n}^{2} + 4n - 96 = 0 \\ {n}^{2} - 12n + 8n - 96 = 0 \\ n(n - 12) + 8(n - 12) = 0 \\ (n - 12)(n + 8) = 0 \\ n = 12$

So,

The numbers are,

13 and 15.