Question

sum of two consecutive multiple 32 is 416 find the value ​

Answer 1

ANSWER:

Given:

• Sum of 2 consecutive multiples of 32 = 416.

To Find:

• The 2 numbers

Solution:

Let the multiples of 32 be 32x and 32(x + 1).

We are given that,

⇒ 32x + 32(x + 1) = 416

Opening bracket,

⇒ 32x + 32x + 32 = 416

Transposing 32 to RHS,

⇒ 64x = 416 - 32

⇒ 64x = 384

Transposing 64 to RHS,

⇒ x = 384/64

⇒ x = 6.

So, the numbers are:

• 32x = 32(6) = 192
• 32(x + 1) = 32(7) = 224

Hence, the 2 consecutive multiples of 32 whose sum is 416 are 192 and 224.