sum of two consecutive multiples of 10 is 210 find the smaller multiple
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Answered by
2
Answer:
Let us assume the two consecutive multiples of 10 be 10x and 10x + 10.
So,
Sum of two consecutive multiples of 10 = 10x + 10x + 10 = 210
20x + 10 = 210
20x = 210 – 10
20x = 200
x = 200/20
x = 10
∴the two consecutive multiples of 10 are 10x = 10 × 10 = 100
10x + 10 = (10 × 10) + 10
= 110
Hence, the smaller multiple of 10 is 100.
Answered by
0
Answer:
Step-by-step explanation:
let the two numbers be x& x+10
x+x+10=210
2x+10=210
2x=210-10
2x=200
x=200/2=100
x+10=100+10=110
smaller multiple=2
two numbers are 100;110
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