Sum of two consecutive multiples of 6 is78
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Let the multiples be = x, (x+6)
According to question
x + (x+6) = 78
x + x + 6 = 78
2x + 6 = 78
2x = 78 - 6
2x = 72
x = 72 / 2
x = 36
1st multiple = x = 36
2nd " = x + 6 = 36 + 6 = 42
Answer = 36, 42
According to question
x + (x+6) = 78
x + x + 6 = 78
2x + 6 = 78
2x = 78 - 6
2x = 72
x = 72 / 2
x = 36
1st multiple = x = 36
2nd " = x + 6 = 36 + 6 = 42
Answer = 36, 42
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