sum of two consecutive natural numbers 31. what is the difference of their squares
Answers
Answered by
20
one number = x
consecutive number = x +1
x + x+ 1 = 31
2x = 30
x = 15
numbers= 15, 16
difference in squares = 16^2 - 15^2
= 256 - 225
= 31
consecutive number = x +1
x + x+ 1 = 31
2x = 30
x = 15
numbers= 15, 16
difference in squares = 16^2 - 15^2
= 256 - 225
= 31
Answered by
7
n+n+1=31
2n=30n=15
numbers are 15,16
16×16-15×15
difference is also 31
2n=30n=15
numbers are 15,16
16×16-15×15
difference is also 31
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