sum of two consecutive numbers is 145. Find the numbers.
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Answer:
Let the smallest of two consecutive integer be x, thus other consecutive integer be x + 1.
As per the statement, sum of these two consecutive integers is 145. As such
x + x + 1 = 145
2x + 1 = 145
2x = 145 - 1
2x = 144
x = 144/2
x= 72
The smallest of two consecutive integers is 72. Other integer is
x + 1 = 72 + 1 = 73
Thus two consecutive integers are 72 and 73
Answer two consecutive integers are 72 and 73
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Answer:
n²+(n+1)²=145,=n²+n²+2n+1=145,2n²+2n=144,n²+n=72,n²+n−72=0.Jan 27, 2016
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